feature 1.处理零数量零单价的问题

order-management-consumer/src/main/java/com/dxhy/order/consumer/utils/BeanTransitionUtils.java

@@ -3611,6 +3611,12 @@ public class BeanTransitionUtils {
                 }
                 ddmxxxBO.setPH(detail.getCHARG());
                 ddmxxxBO.setKB(ObjectUtil.isNull(detail.getKTYPE())?"":detail.getKTYPE()+(ObjectUtil.isNull(detail.getKNAME())?"":detail.getKNAME()));
+                BigDecimal decimal = new BigDecimal("0");
+                if(StringUtils.isNotBlank(ddmxxxBO.getJE()) && decimal.compareTo(new BigDecimal(ddmxxxBO.getJE())) != 0) {
+                    ddmxxxBO.setJE("");
+                } else if (StringUtils.isNotBlank(ddmxxxBO.getSPSL()) && decimal.compareTo(new BigDecimal(ddmxxxBO.getSPSL())) != 0) {
+                    ddmxxxBO.setSPSL("");
+                }
                 //判断单价*数量与金额的差额大于0.01，大于的话则反算
                 //判断小数点后位数,默认为8位,如果为全电,为15位
                 if(!ConfigureConstant.STRING_1.equals(ddmxxxBO.getFPHXZ())){
@@ -3682,6 +3688,10 @@ public class BeanTransitionUtils {
     }
 
     public static void main(String[] args) {
+        BigDecimal decimal = new BigDecimal("0");
+        if( decimal.compareTo(new BigDecimal("0")) != 0){
+            System.out.println("00992424");
+        }
         String zje = DecimalCalculateUtil.bigDecimalAdd("2", "1");
         if(DecimalCalculateUtil.stringCompare(zje,"3") != 0){
             System.out.println("00");